## Data interpretation -Tabular data Interpretation questions

**Question1**. The following table gives the sales of batteries manufactured by a company over the years. Study the table and answer the questions that follow

__NUMBER OF DIFFERENT TYPES OF BATTERIES SOLD BY A COMPANY OVER THE YEARS (NUMBERS IN THOUSANDS)__1.The total sales of all the seven years is the maximum for which battery ?

- (a) 4AH
- (b) 7AH
- (c) 32AH
- (d) 35AH
- (e) 55AH

2.What is the difference in the number of 35AH batteries sold in 1993 and 1997 ?

- (a) 24000
- (b) 28000
- (c) 35000
- (d) 39000
- (e) 42000

3.The percentage of 4AH batteries sold to the total number of batteries sold was

maximum in the year :

- (a) 1994
- (b) 1995
- (c) 1996
- (d) 1997
- (e) 1998

4.In the case of which battery there was a continuous decrease in sales from 1992 to 1997 ? -

- (a) 4AH
- (b) 7AH
- (c) 32AH
- (d) 35AH
- (e) 55AH

5.What was the approximate percentage increase in the sales of 55AH batteries in 1998

compared to that in 1992 ?

- (a) 28%
- (b) 31%
- (C) 33%
- (d) 34%
- (e) 37%

__Solutions:__Sol. 1. (c) : The total sales (in thousands) of all the seven years for various batteries are :

For 4AH= 75 + 90 + 96 + 105+ 90 + 105 + 115 = 676

For 7AH = 144 + 126 + 114 + 90 + 75 + 60 + 85 = 694

For 32AH = 114 + 103 + 75 +‘150 + 135 + 165 + 160 = 901

For 35AH= 102+84+105+90+75+45+100=-601

For 55 AH = 108 + 126 +1135 + 75 + 90 + 120 + 145 = 799.

Clearly, sales. are maximum in case of 32AH batteries.

Sol.2. (d) : Required difference = [(84 - 45) * 1000] = 39000.

Sol.3. (d) : The percentages of sales of 4AH batteries to the total sales in different

years are : -

For 1992 = [(75/543) * 100]% = 13.81%;

For 1993 = [(90/528*100]% =17.05%

For 1994=[(96/525)*100]%=18.29%

For 1995=[(105/510)*100]%=20.59%

For 1996=[(96/465)*100]%=19.35%

For 1997=[(105/495)*100]%=21.21%

For 1998=[(115/605)*100]%=19.01%

Clearly percentage is maximum in the year 1997.

Sol.4.(b)From the table it is clear that the sales of 7AH batteries have been decreasing continuously from 1992 to 1997.

Sol.5.(d) :Required Percentage =[{(145-108)/108}*100]%=34.26%

**Question2.**The following table gives the percentage of marks obtained by seven students in six different subjects in an examination. Study the table and answer the questions based on it. The numbers in the bracket give the maximum mark in each subject

- (a) 409
- (b) 419
- (c) 429
- (d) 439
- (e) 449

2. What is the overall percentage of Tarun ? .

- (a) 52.5%
- (b) 55%
- (c) 60%
- (d) 63%
- (e) 64.5%

3. What are the average marks obtained by all the seven students in Physics ? (rounded off to two digits after decimal)

- (a) 77.26
- (b) 89.14
- (c) 91.37
- (d) 96.11
- (e) 103.21

4. The number of students who obtained 60% and above marks in all the subjects is :

- (a) 1
- (b) 2
- (c)3
- (d) None
- (e) None of the above

5. In which subject is the overall percentage the best ?

- (a)History
- (b) Maths
- (c) Physics
- (d) Chemistry
- (e) Geography

__Solutions:__Sol.1. (e) : Aggregate marks obtained by Sajal

= [(90% of 150) + (60% of 130) + (70% of 120) + (70% of 100) + (90% of 60)+ (70% of 40)] = 135 + 78 + 84 + 70 + 54 + 28 = 449.

Sol.2.(c) : Aggregate marks obtained by Tarun= [(65% of 150)'+ (35% of 130) + (50% of'120) + (77% of 100) + (80% of 60)+ (80% of 40)] = 97.5 + 45.5 + 60 + 77 + 48 + 32 = 360.

Total maximum marks (of all the six subjects) = (150 + 130 + 120 + 100 + 60 + 40) = 600.

Overall percentage of Tarun = [(360/600)*100]% = 60%

Sol.3.(b) : Average marks obtained in Physics by all the seven students

= (1/7) * [(90% of 120)+ (80% of 120) + (70% of 120) + (80% of 120)+ (85% of 120)+ (65% of 120)+ (50% of 120))=89.14

Sol.4.(b). From the ‘table it is clear that Sajal and Rohit have 60% or more marks in each of the six subjects.

Sol.5.(b). We shall ﬁnd the overall percentage (for all the seven students) with respect to each subject.

The overall percentage for any subject is equal to the average of percentage obtained by all the seven students since the maximum marks for any subject is the same for all the students.

Therefore, Overall percentage for :

(i) Maths = [(1/7)*(90 + 100 + 90 + 80 + 80 + 70 + 65)]%= 82.14%.

(ii) Chemistry = [(1/7)* (50 + 80 + 60 + 65 + 65 + 75 + 35)]%= 61.43%.

(iii) Physics = [(1/7)*(90 + 80 + 70 + 80 + 85 + 65 + 50)]%=74.29%.

(iv) Geography = [(1/7)* (60 +,40+ 70 + 80 + 95 + 85 + 77)]%= 72.43%.

(v) History =[(1/7)*(70 + 80 + 90 + 60 + 50 + 40 + 80)%=67.14%

(vi) Computer Science =(80+70+70+60+90+60+80)]%=72.86

Clearly percentage is highest for maths.

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