## Time distance and speed formulas and shortcuts for bank exams

Time distance and speed formulas and shortcuts for bank exams:On an average you can found 2-3 question on**Time ,distance and speed**in every

**bank exams**.By understanding few formulas and shortcuts you can score full mark from this section.We have provided main

**formulas and shortcuts of time,distance and speed for IBPS Clerk and PO exams**.

Relation between time distance and speed is given by the equation

speed=distance/time

Unit of speed is km/hr or m/s

If speed is given in km/hr,then inorder to convert it in to m/s multiply by 5/18

1km/hr=5/18m/s

If speed is given in m/s,then inorder to convert it in to km/hr multiply by 18/5

### Ratio

- If ratio of speed of two moving object is a:b, then ratio between times taken for covering same distance is b:a.
- If two objects A and B moving in opposite direction from two different places reach at common point in t1 and t2 hrs respectively Then Speed of A:Speed of B=sqrt(t2/t1)

**Average speed**

- average speed=total distance/total time taken.
- If a moving object covers a certain distance with a speed of x km/hr and again covers same distance with a speed of ykm/hr, then average speed is 2xy/(x+y).
- If a moving object covers a certain distance with a speed of x km/hr and again covers same distance with a speed of ykm/hr and again with zkm/hr,then average speed is=3xyz/(xy+yz+xz)

### Points to be noted while doing 'train and time' problems

- If two trains are travelling in same direction ,then their relative speed is equal to difference of their speeds.Then Time taken by the fast train to cross the slower train is =
**Sum of lengths of both trains/difference of their speed** - If two trains are travelling in opposite direction ,then their relative speed is equal to sum of their speeds.Then time taken to pass one another is =
**Sum of lengths of both trains/sum of their speed.** - when a train is clearing a pole or a point, then distance covered by train is equal to its length
- When a train is covering a platform or bridge or tunnel ,then distance covered by train is equal to sum of the length of train and the length of platform/tunnel/bridge.
- When a moving train crosses another train, then distance covered is equal to sum of lengths of both trains.

Example:A 480-metre-long train crosses a platform in 140 seconds. What is the speed of the train?

Ans:Cannot be determined,since length of platform is not given

Example:A train 100m long is running at 21km/hr and another train 150m is running at 36km/hr in the same direciton.how long will the faster train take to pass the other train?

Sum of length of both train=100+150=250m

difference of their speed is=36-21 km/hr=15km/hr=15*(5/18) m/s=25/6 m/s

Time taken=250/(25/6)=60 seconds.

### Boat and stream problems

- If speed of stream=xkm/hr and speed of boat in still water is ykm/hrthen speed of boat in downstream=x+y km/hr speed of boat in upstream=y-x km/hr
- If speed of boat in upstream and speed of boat in down stream is given then, speed of boat in still water=1/2(speed in upstream+speed in downstream) speed of stream=1/2(Speed in downstream - speed in upstream)

Example: A boat is moving at 30 km/hr upstream, when it travels down stream its speed is 36km/hr.What is the speed of boat in still water and what is the speed of stream?

Speed of boat in still water=1/2 (30+36)=66/2=33 km/hr.

speed of stream=speed of boat downstream-speed of boat in still water

=36-33=3km/hr

*Note:*

A person walks at x kh/hr he reaches destination t1 hrs late,if he walks at y km/hr,then reaches t2 hrs early

then distance to the destination =(xy/(y-x)) * (t1+t2)

Example:A person walking at 2km/hr reaches his office 6 minutes late .If he walks at 3km/hr he reaches there 6 minute early. How far is the office from his house?

Distance=(2*3)/(3-2) *((6+6)/60)=6*12/60=1.2 km .

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