# Time distance and speed shortcuts for bank po/clerk

## Time distance and speed formulas and shortcuts for bank exams

Time distance and speed formulas and shortcuts for bank exams:On an average you can found 2-3 question on Time ,distance and speed in every bank exams.By understanding few formulas and shortcuts you can score full mark from this section.We have provided main formulas and shortcuts of time,distance and speed for IBPS Clerk and PO exams.

Relation between time distance and speed is given by the equation
speed=distance/time
Unit of speed is km/hr or m/s
If speed is given in km/hr,then inorder to convert it  in to m/s multiply by 5/18
1km/hr=5/18m/s
If speed is given in m/s,then inorder to convert it  in to km/hr multiply by 18/5

### Ratio

• If ratio of speed of two moving object is a:b, then ratio between times taken for covering same distance is b:a.
• If two objects A and B moving in opposite direction from two different places  reach at common point in t1 and t2 hrs respectively                 Then Speed of A:Speed of B=sqrt(t2/t1)
Average speed
• average speed=total distance/total time taken.
• If a moving object covers a certain distance with a speed of x km/hr and again covers same distance with a speed of ykm/hr, then average speed is 2xy/(x+y).
• If a moving object covers a certain distance with a speed of x km/hr and again covers same distance with a speed of ykm/hr and again with zkm/hr,then average speed is=3xyz/(xy+yz+xz)

### Points to be noted while doing 'train and time' problems

• If two trains are travelling in same direction ,then their relative speed is equal to difference of their speeds.Then Time taken by the fast train to cross the slower train is                                                                            =Sum of       lengths of both trains/difference of their speed
• If two trains are travelling in opposite direction ,then their relative speed is equal to sum of their speeds.Then time taken to pass one another is   =Sum of lengths of both trains/sum of their speed.
• when a train is clearing a pole or a point, then distance covered by train is equal to its length
• When a train is covering a platform or bridge or tunnel ,then distance covered by train is equal to sum of the length of train and the length of platform/tunnel/bridge.
• When a moving train crosses another train, then distance covered is equal to sum of lengths of both trains.
Example:A 480-metre-long train crosses a platform in 140 seconds. What is the speed of the train?
Ans:Cannot be determined,since length of platform is not given

Example:A train 100m long is running at 21km/hr and another train 150m is running at 36km/hr in the same direciton.how long will the faster train take to pass the other train?
Sum of length of both train=100+150=250m
difference of their speed is=36-21 km/hr=15km/hr=15*(5/18) m/s=25/6 m/s
Time taken=250/(25/6)=60 seconds.

### Boat and stream problems

• If speed of stream=xkm/hr and speed of boat in still water is ykm/hrthen speed of boat in downstream=x+y km/hr                                           speed of boat in upstream=y-x km/hr
• If speed of boat in upstream and speed of boat in down stream is given then,                                                                                        speed of boat in still water=1/2(speed in upstream+speed in downstream)                                                                                                      speed of stream=1/2(Speed in downstream - speed  in upstream)
Example: A boat is moving at 30 km/hr upstream, when it travels down stream its speed is 36km/hr.What is the speed of boat in still water and what is the speed of stream?
Speed of boat in still water=1/2 (30+36)=66/2=33 km/hr.
speed of stream=speed of boat downstream-speed of boat in still water
=36-33=3km/hr
Note:
A person walks at x kh/hr he reaches destination t1 hrs late,if he walks at y km/hr,then reaches t2 hrs early
then distance to the destination =(xy/(y-x)) * (t1+t2)

Example:A person walking at 2km/hr reaches his office 6 minutes late .If he walks at 3km/hr he reaches there 6 minute early. How far is the  office from his house?
Distance=(2*3)/(3-2) *((6+6)/60)=6*12/60=1.2 km .

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