Pipe And Cistern questions for Bank Exams

Pipe And Cistern questions for Bank Exams:In every bank exams ,under quantitative section,there will be at least one question on" pipe and cistern". Solving these type of question is similar to solving Work and Time problem .An average student can solve pipe and cistern problems. But as you know, in bank exams time management matters a lot.We are sharing some important Pipe and Cistern Shortcuts.Hope you will find it useful in upcoming exams.

Pipe and cistern important shortcut formulas

1.If two pipes A and B 

A can fill a tank in x hrs
and B can fill the same tank in y hrs
If both pipes are opened simultaneously ,then time taken to fill the tank is 

Work done by both pipes together in 1hr=1/x +1/y

2.If two pipes A and B
A can fill a tank in x hrs
and B can empty the same tank in y hrs
If both pipes are opened simultaneously ,then time taken to fill the tank is =

Work done by both pipes together in 1hr=1/x -1/y

3.If three pipes A ,B and C
A can fill a tank in x hrs
B can fill the same tank in y hr
and C takes z hrs for filling the same tank.
If three pipes are opened simultaneously ,then time taken to fill the tanks is

Work done by three pipes together in 1hr=1/x +1/y +1/z

Example: A can fill the tank in 28hrs
B can fill the tank in 14 hrs
and C takes 7hrs.
If all three pipes are opened simultaneously ,how long it will take to fill the tank?

Solution:time taken=(28*14*7*)/(28*14 + 14*7 + 28*7)
To solve this quicker  find out LCM(28,14,7)
we get 28
Time taken =28/(28/28 + 28/14 + 28/7)
=28/(1+2+4)
=28/7
=4

4.If A can fill a tank in x hrs,B can fill the same tank in y hr and C takes z hrs for emptying  the same tank.
If three pipes are opened simultaneously time taken to fill the tank is=

Work done by three pipes together in 1hr=1/x +1/y -1/z

Example: A can empty the tank in 28 hrs, B can fill the tank in 14 hrs, and C takes 7 hrs for filling.
If all three pipes are opened simultaneously ,how long it will take to fill the tank?
Solution:time taken=(28*14*7*)/(28*14 - 14*7 + 28*7)
To solve this quicker  find out LCM(28,14,7)
we get 28
Time taken =28/(-28/28 +28/14 + 28/7)
=28/(-1+2+4)
=28/5
=5.6 hrs
=5 hr 36 minutes

Pipes and Cisterns Practice questions [PDF]

If you like this shortcut trick on pipe and cistern,then like and share it with your friends.If any doubt,then comment below

[pipes and cisterns tricks pdf pipes and cisterns aptitude questions with answers,pipes and cisterns problems with solutions pdf,pipes and cisterns shortcuts pdf,pipes and cistern shortcuts and tricks- easiest trick seen ever part 2.pipes and cisterns concepts,pipes and cisterns formula pdf pipe and cistern in hindi]

simon     00:07:00     1 comment:

Profit and loss formulas and shortcuts for ibps,sbi po and clerk

Profit and loss problems for bank exam:In every bank exam,at least 1-2 questions will be from profit and loss section.By understanding few simple formulas and shortcuts you can easily score full mark from this section.Here we are sharing some important formulas and shortcut tricks to solve profit and loss problems faster.

Basic formulas for profit and loss

• Cost Pice:Cost price(C.P)is the price at which a particular article is bought.
• Selling Price:Selling price(S.P) is that price at which a particular item is sold.
• If an article is sold at 40% profit,then S.P=140% 0f C.P
• If an article is sold at 40% loss, then S.P=60% of C.P
• The profit or loss percentage is always calculated based on C.P
• If P sold an article at a profit R1% to Q.Q sold it to R at a profit of R2% and R sold it to S at a profit of R3%.Then money spent by S for buying article 

Example:A sells a radio to B at a gain of 10% and B sells to c at a gain of 5%.If C pays Rs.462 for it,what did it cost to A?
C.P of radio to C=C.P of radio to A * (1+10/100)(1+5/100)
=> 462=C.P of radio to A * 110/100 *105/100=>C.P of radio to A=(462*100*100)/(105*110)=400

• If there are two successive profits (R1% and R2%) obtained on an article then

Example:A dishonest shopkeeper deceives by 15% at the time of purchase of article and also 15% at the time of sale.Find out the profit percentage
Profit%=15+15+(15*15 / 100)=30 + 225/100 =30+2.25=32.25%.

• If a seller mark P% above cost price and gives a discount of Q%,the final 

Example:A car costs a dealer Rs.50,000.Dealer raised price by Rs.10,000 and then deducted 4% of new price.What is the profit/loss %?
Ans: Let P be the percentage of price raised=(10000/500000) * 100 =20%
Discount %=4%
profit %=(20-4- 20*4/100 ) =15.2%

• When a person sells two similar items(Same S.P), one at a profit of x%, and other at a loss of x%, then the seller always incurs a loss given by 
• If a seller professes to sell an article at C.P , but uses false weights, then

Hope you will find this article on profit and loss shortcut formulas for bank test useful in upcoming bank exams.

• Download Profit and Loss Practice questions Pdf

[Related tags:profit and loss shortcut tricks pdf,how to solve profit and loss problems quickly,profit and loss tricks in hindi,profit and loss tricks for bank po,profit and loss tricks for ssc cgl,profit and loss problems with solutions,profit loss aptitude questions answers pdf,profit and loss formulas and examples]

simon     00:04:00     No comments:

Work and Time problems shortcuts for bank tests

Work and Time shortcut tricks for bank exams:In every competitive exam we have to deal with varieties of quantitative aptitude questions .In almost every competitive exam, work and time problem is a regular question under quantitative section.In bank PO and clerk exams there will be at least 2-3 questions on work and time.By understanding the basic concept and memorizing a few shortcut formulas, you  can score full mark for these questions.Here we are sharing some useful Work and Time shortcut tricks for bank exams.

Basic point to remember while solving work and time problems:First of all work done in 1 day is calculated.If a person completes a work in x days,then Work done by that person in one day is 1/x.

Shortcut formula for solving work and time problems

If A can do a work in x days and B can do the same work in y days,then  A and B together can finish the work in 

This is the first and foremost shortcut formula for solving work and time problems.For understanding better, derivation of this formula is given below.

Derivation of above formula:

    Work done by A in one day=1/x

    Work done by B in one day=1/y

    Work done by A and B together in 1 day=1/x+1/y

    Then  total days taken to complete the work by A and B together=1/ Work done by A and      B together in 1 day

    =1/(1/x+1/y)

    =1/((x+y)/xy))

    =xy/(x+y)

Example:If A can do a work in 8 days and B can do the same work in  days,in how many days A and B together can finish the work

Ans:Applying above formula 

 no of days taken to finish the work=8*6/(8+6)

 Instead of solving this directly take the LCM of 8 and 6

 8*6/(8+6)=LCM(8,6)/(LCM(8,6)/8 + LCM(8,6)/6)=24/(3+4)=24/7=3 3/7

Important points to be noted while solving work and time problems

1. If A completes a work in x days and B completes the same work in y days then ratio of work done by A and B in one day will be y:x
2. If A can finish the work in x days ,B can finish the same work  in y days and C finishes it in z days, then number of days taken to complete the work if all three work together is   
3. If A&B together can finish the work in x days,B&C together finishes in  y days and C&A together finishes in z days,then work done by A,B and C together in 1 day is                            
4. If a man can do x/y of work in 1 hr,then he will take y/x hrs to finish the work.

Work and Time - Practice questions(Solved)

Question1:Ganesh ,Ram and Sohan together can do a work in 16 days. If Ganesh and Ram together can do a the same work in 24 days then, how long will take Sohan to do the same work?

Solution: Work done by three of them together in 1 day= 1/16............(1)

               Work done by Ganesh and Ram together in 1 day= 1/24.....(2)

               So,work done by Sohan in one day=(1)- (2)=(1/16) - (1/24)=1/48

               =>Total days taken by Sohan to complete the work alone= 48 days.

Question2:15 men can complete a work in 10 days while 20 boys can complete the same work in 15 days .How many days will 10 men and 10 boys together take to complete the same work

Solution:Work done by one man in one day=1/(15*10)

              Work done by one boy in one day=1/(20*15)

              Work done by 10 men and 10 boys in one day=10[ 1/(15*10) + 1/(20*15)] 

              Days taken=1/Work done by 10 men and 10 boys in one day

                                =10 days

Question3:16 men can do a piece of work in 16 days .4 days after they started the work, 8 more men joined them. How many days will they now take to complete the remaining work

Solution:Work done by 1 man in 1 day=1/(16*16)

              Work completed by 16 men in 4 days= 4[1/(16*16)]*16=1/4

               Remaining work= 1- 1/4= 3/4

               Total men now= 16+ 8=24

               24 men do 3/4 work 

                =>24*number of days*Work done by 1 man in 1 day=3/4

                =>24*number of days* 1/(16*16)=3/4

                =>number of days=8 days

Download Work and Time Practice questions PDF ebook

Question4:A and B together can complete a piece of work in 6 days. B and C can complete the same work in 8 days.A and C can finish it in 12 days. If they all work together, how long it will take to finish the work
 Solution:Applying the formula
               Work done by A,B & C together in one day= ½(1/6 +1/8 + 1/12)=9/48
                => days taken to complete the work by A,B & C together =48/9 days

You may also like to read

• Time and distance shortcut tricks
• shortcut tricks for profit and loss
• shortcut tricks for quantitative aptitude for bank exams

Those who want further explanation may drop your request in comment section below.If you find this post on Work and Time shortcut tricks useful, then don't hesitate to share it with your friends.Like us on facebook to get articles like this.
[Tags:time and work shortcuts tricks pdf,time and work shortcut tricks videos,time and distance shortcut tricks,time and distance shortcuts tricks in hindi,shortcut tricks for profit and loss,shortcut tricks for syllogism,shortcut tricks for aptitude,shortcut tricks for quantitative aptitude for bank exams]

simon     23:48:00     3 comments:

Mixture and Alligation for bank PO and clerk exams

Mixture and Alligation questions shortcuts for bank exams:Almost all IBPS PO and Clerk examinations contain mixture and alligation problems.This is the area from where you can easily score few marks by understanding some formulas and shortcuts.Here we are sharing some important mixture and alligation problem formulas and tricks.If two different commodities, one of which is cheaper than the other, are mixed to obtain a new mixture, Cost Price of unit value of this new mixture is called mean price.

Basic formula for mixture and alligation problem

If two different commodities, one of which is cheaper than the other, are mixed to obtain a new mixture, Cost Price of unit value of this new mixture is called mean price.This is the the first and foremost formula you should remember to solve mixture and alligation questions.

Example:A merchant blends two types of rice costing Rs.15 per kg and Rs.20 per kg .In what ratio should these two rice to be mixed so that resulting mixture may cost Rs.16.50 per kg.

Note:
When water is mixed in milk or any liquid in such away that resulting mixture gives a profit of x% when sold at C.P of milk/liquid. Then ratio of Quantity water:Quantity of milk=x:100
Eg: In what ratio should water be mixed in milk so that seller makes a profit of 10% when mixture is sold at cost price of milk? Water : milk =10:100=1:10.

Solving mixture and alligation problems (If more than two different commodities are mixed)

Example:If A cost 95 per kg,B cost 60 per kg,C cost 90 per kg and D cost 50 per kg. They are blended in such a way that the cost price of resulting mixture is 80.In what ratio four commodities are mixed?
To solve these kind of problems follow the steps below
Step1: Arrange them in ascending order
50

60
90
95
Step2: Make couples ,one is above mean price and other is below mean price

Step3:Now find difference between price and mean price and write it opposite to the price linked to it.

Step3: Required ratio Qt of A: Qt of B: Qt of C: Qt of D=15:10:20:30=3:2:4:6

Note:
In ‘n’ equal sized vessels two liquid P and Q are filled in the ratio p1:q1,p2:q2,p3:q3……….. pn:qn respectively
When they are mixed,

If vessels are of different quantities say x1,x2,x3….xn.

Removal and replacement problems

A vessel contains x litre of milk. y litre is drawn and replaced by water.Then again y litre of solution is replaced by water. If this process is repeated ‘n’ times,then

Example:9 litre are drawn from a cask full of milk and then filled with water.9 litre of mixture are drawn and cask is again filled with water.Quantity of milk now left in the cask is to that of water in at is as 16:9.What is the capacity of cask in litre?
Ans:let x be the capacity of cask which is=quantity of initial milk,

Mixture and alligation practice questions for bank tests

Qs1.In what ratio must a seller mix two varieties of pulses costing Rs. 12 and Rs. 20 per kg respectively so as to get a mixture worth Rs.15 ?
A. 5 : 7
B. 5 : 3
C. 7 : 3
D. 3 : 5

Qs2.How many kilogram of sugar costing Rs. 9 per kg must be mixed with 27 kg of sugar costing Rs. 7 per kg so that there may be a gain of 10% by selling the mixture at Rs. 9.24 per kg?
A. 63kg
B. 72 kg
C. 57 kg
D. 56kg

Qs3. A container contains 40 litres of milk. From this container 4 litres of milk was taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container?

A.26.90 litres

B.29.16 litres

C.27.55 litres

D.30.70litres

Qs4.A and B are two alloys of gold and copper prepared by mixing these metals in the ratio 7:2 and 7:11 respectively. If equal quantities of alloys are melted to form a third alloy C the ratio of gold and copper in the alloy C?
A.5:7
B.7:5
C.2:5
D.5:2

Qs.5.13. How much water must be added to 10 ltr of 80% solution acid to reduce it to a 50% solution ?
A.20 ltr
B.40 ltr
C.80 ltr
D.60 ltr

Answers:1.B,2.A,3.B,4.B,5,D

	Download Mixture and alligation Practice set(Fully solved-15 questions).PDF

If you find this Mixture and alligation formulas and tricks for bank exams useful share it

[mixture and alligation tricks pdf,mixture and alligation problems tricks,mixture and alligation short tricks mixture and alligation formula,mixture and alligation solved problems,mixture and,alligation concepts,alligation mixture tutorial,mixture and alligation]

simon     11:30:00     No comments:

Simple Interest and Compound interest shortcut formulas and trick for bank exams

Every bank exam contains simple interest and compound interest questions.Every candidate can solve these questions.But in bank exams, time management is an important factors.Shortcut formulas play an important role in time management.Here we are sharing important formulas and shortcuts for solving simple interest and compound interest faster.Hope this will save your few valuable minutes during next exam.

Simple Interest

Simple interest is given by the formula I= PRT /100

P=PRINCIPLE R=RATE OF INTEREST per annum T=TIME PERIOD

• If principle doubles in T years,then R=100/T
• If principle triples in T years ,then R=200/T
• if principle becomes  four times in T years,then R=300/T

Compound Interest

Compound interest is given by,

                                  

 Amount after T years ,

                                      

• If rate is R1,R2 & R3 for 1st,2nd and 3rd year respectively then amount is ,

                              

• If difference of S.I and C.I is given for 2 years

                             

Example:Difference between simple interest on certain sum of money for 2 years at 4% and compound interest for same period at same rate is 200.Find the  sum

Ans:Principle=difference*(100/2)^2=200*100/2*100/2=RS 500000.

• If difference of S.I and C.I is given for 3 years                                  

• If amount compounded half yearly R will be replaced by R/2 and T will be replaced by 2T

                                     

• If amount compounded quarterly R will be replaced by R/4 and T will be replaced by 4T

                                            

Eg :Find the compound interest of Rs.10,000 in 9 months at 4%per annum interest payable quarterly.

Rate=4/4=1%,Time period= 9 months=3 quarter years.

CI=10,000*((1+1/100)^3 -1)=303.01.

• If an amount A becomes B in T1 years ,then at T2 years                                        

Shortcut for finding compound interest 

In some cases evaluation of C.I using formula will be time consuming. Here is an alternate method for calculating compound interest.

Let Principle = P, Compound interest % =  x % per annum , Time period=T

If T=2 , 

Total interest percentage for the first year=x,

Total interest percentage for the second year=x + x% of x= x+ (x*x/100)

Then effective percentage of interest =2x + x*x/100

Then C.I=(2 x + x*x/100) % of P= P*[(2x + x*x/100)/100]

If T=3

Total interest percentage for the first year=x,

Total interest percentage for the second year=x + x% of x= x+ (x*x/100)

Total interest percentage for the third year= x + x % of ( x + x+ x*x/100) =x+ x*( x + x+ x*x/100)/100)

Then effective percentage of interest= x+ x+ (x*x/100) + x+ x*( x + x+ x*x/100)/100)= 3x+ (x*x/100) +x*( 2x + x*x/100)/100)

You may be finding  formulas lengthy, but you will find this method simpler after practicing some problems.Especially if T=2, then this method will be much faster than conventional method using the commonly used formula.

Now let us solve two problems using above method.

Example 1 : What is the compound interest paid on a sum of Rs.3000 for the period of 2 years at 10% per annum.

1. 630
2. 620
3. 610
4. 600

Solution= Interest % for 1st year= 10

                 Interest % for 2nd year= 10+ 10% of 10= 10+ 10 *10/100=11

                 Total % of interest= 10 + 11=21

                 Total interest = 21 % 3000= 3000 * (21/100)= 630

So, answer is option 1

Example 2:What is the compound interest paid on a sum of Rs.3000 for the period of 3 years at 10% per annum.

1. 900
2. 930
3. 990
4. 993

Solution= Interest % for 1st year= 10

                 Interest % for 2nd year= 10+ 10% of 10= 10+ 10 *10/100=11

                 Interest % for 3rd year= 10+ 10%(10+11)=10+ 2.1=12.1

                 Total % of interest= 10 + 11+12.1=33.1

                 Total interest = 33.1 % 3000= 3000 * (33.1/100)= 993

So, answer is option 4

Simple interest, compound interest practice questions

1.A man derives his income from an investment of Rs.2000 at a certain rate of interest and Rs.1600 at 2% higher. The whole interest in 3 years is Rs.960. Find the rate of interest.

Answer:8%

2.A man buys a house and pays Rs.8000 cash and Rs.9600 at 5 year credit at 4% per annum simple interest. Find the cash price of the house.

Answer: Rs.16000

3.The simple interest on a certain sum of money for 3 years at 4% is Rs.303.60. Find the compound interest on the same sum for the same period at the same rate.

Answer:315.90

4.If a certain sum given on simple intrest doubles in 20 years. In how many years will it be four times?

Answer:60 years

5.A sum of money placed at compound interest doubles itself in 4 years. In how many years will it amount to 8 times.

Answer:12 years

• Simple Interest Compound Interest Practice questions PDF(15 questions Fully solved with shortcuts)

               

If you need explanation for any of the above practice questions you can comment below.Share this article on  "Simple interest and compound interest Shortcuts for bank PO and Clerk exams" and practice questions of simple interest and compound interest with you friend.Like us on facebook to get more study materials for bank PO and clerk.

simon     13:16:00     4 comments:

Ratio,proportions and Fractions for competitive exams(bank po,clerk,ssc,cat,mat,upsc etc..)

Ratio and Fractions shortcuts and tricks:In most of the competitive exams quantitative part will be time consuming when compared with other sections.This is same in case of bank exams also.To improve your overall quantitative aptitude speed ,you must me thorough with basic maths rules and shortcuts. Here we are sharing some important rules and shortcut tricks for ratio proportion and fractions. This will not only help you in solving ratio and fraction questions faster, but also improve your overall maths speed.Here we have covered all important rules and formulas of ratio,proportion and fractions and examples are included for better understanding.

Ratio and proportion-Important rules and shortcuts

Example:If P:Q=2:3, Q:R=4:5 then P:R=?

P/R=(P/Q)*(Q/R)=2/3*4/5=8/15,thus P:R=8:15

Example:P:Q:R=2:3:4,then P/Q:Q/R:R/P=?

P/Q:Q/R:R/P=2/3:3/4:4/2=8:9:24

Example:If 2P=3Q=4R then P:Q:R=?

Let 2P=3Q=4R=K, 
we get P=K/2,Q=K/3,R=K/4 
=> P:Q:R=K/2:K/3:K/4=1/2:1/3:1/4=6:4:3

Example:P:Q=1:2,Q:R=4:5,R:S=10:3 then P:Q:R:S=?

 Make the  Q term in first and second fraction same and make the R term similar in second and third fractions as follows

P:Q:R:S=2:4:5:3/2=4:8:10:3

Comparison of ratios and Fractions

Method1:To compare two fractions  we can  make either denominators same or numerators same.

Example:2/5 and 3/10

To find out which is greater, make denominators same.We get 4/10 and 3/10.From this we can conclude,2/5>3/10

                            or make numerator same

Fractions will become 6/15 and 6/20,obviously 6/15>6/20.

Method2:This method can be applied if difference between numerator and denominator is same for all given fractions.

Example:1/2,3/4,7/8. Here 2-1=4-3=8-7=1.In such cases, just look at the numerator .Smaller the numerator will be smaller fraction.1/2<3/4<7/8.

Method3:this method is applicable for all fractions.

If a/b and c/d are fractions under consideration,cross multiply numerator and denominator .ie a*d and c*b.

If a*d>b*c,then a/b>c/d

Example:7/11 and 3/5

cross multiply denominator and numerator.We get 7*5 and 11*3 

Since 7*5>11*3 ,7/11>3/5

Click here for square,square root and cube root shortcuts 

Basic Maths Tricks&shortcuts for division&multiplication 

Don't forget to share Ratios and Fractions shortcuts with your friends  .

[Tags:ratio and proportion tricks,ratio and proportion formula,ratio and proportion problems and solutions,ratio and proportion tricks for ssc,ratio and proportion tricks for bank exams,ratio and proportion tricks in hindi,ratio and proportion pdf,ratio and proportion formulas pdf,shortcut tricks for ratio and proportion,ratio and proportion shortcut trick pdf,fractions tricks and tips,ratio and proportion tricks for bank exams,ratio and proportion tricks for cat,ratio and proportion tricks videos,ratio and proportion tricks for ssc,ratio and proportion tricks in hindi]

simon     10:32:00     1 comment:

Square,square root,cube ,cube roots shortcuts and tricks

Square ,square roots ,cube,cube root shortcuts for bank exams:As you know in bank exams speed is a major factor.In most of the bank exams there will be 10-15 questions from basic maths and simplifications,out of which 2-4 questions will contain square/square root/cube/cube root.Many candidates take it lightly and commit unforced errors.By understanding some basic formulas you can avoid such errors.We are sure that our shortcuts and tricks for squares and cubes will improve your calculation speed considerably. In quantitative section you can save your precious time by practicing maths shortcuts and Tricks.Here we are sharing some useful shortcuts for finding square,square root,cube and cube roots.Hope you will find this useful in upcoming exams.

Square,square root,cube ,cube roots shortcuts and tricks:PDF ebook

Here is the ebook for squares,square roots,cubes cube roots shortcut trick.You can also download this ebook in pdf format from the link provided below.

Click here for Tricks&shortcuts for division&multiplication

If you find this article on Square,square root,cube ,cube roots shortcuts useful  ,then hit like button and share it on Facebook, twitter or google plus.
[Tags:square root and cube root shortcut method,square root and cube root tricks pdf,square root shortcut method pdf,square root tricks in hindi,square root tricks pdf,shortcut for square,square root short trick pdf,shortcut method to find square root of 5 digit number.square root and cube root shortcut method,shortcut tricks for square root and cube root,shortcut to find square root and cube root,cubed square root calculator,square root and cube root table,square root and cube root pdf,square root and cube root problems,square root and cube root worksheet,]

simon     00:29:00     3 comments: